Forum Debian Users Gang

Na podstawie dwoch plikow potrzebuje polaczyc je.

Pierwszy skrypt generuje taki wynik "users.csv"

@admin;;
user1;yes;
user2;yes;
user3;yes;
@develop;;
user4;no;
user5;yes;
user6;no;
user7;no;
@progs;;
user8;no;
user9;no;
user10;no;
...

Drugi skrypt generuje taki wynik "groups.csv"

@admin;path1;12;
user9;path10;1;
@admin;path2;12;
@develop;path3;12;
@develop;path4;1;
@progs;path5;1;
user10;path9;1;
@progs;path6;1;
@progs;path7;1;
@progs;path8;1;
...

Po polaczeniu obu wynikow, chce uzyskac taki koncowy "result.csv"

@admin;path1;12;;;
@admin;path2;12;;;
user1;yes;@admin;path1;12;
user1;yes;@admin;path2;12;
user2;yes;@admin;path1;12;
user2;yes;@admin;path2;12;
user3;yes;@admin;path1;12;
user3;yes;@admin;path2;12;
@develop;path3;12;
@develop;path4;1;
user4;no;@develop;path3;12;
user4;no;@develop;path4;1;
user5;yes;@develop;path3;12;
user5;yes;@develop;path4;1;
user6;no;@develop;path3;12;
user6;no;@develop;path4;1;
user7;no;@develop;path3;12;
user7;no;@develop;path4;1;
@progs;path5;1;
@progs;path6;1;
@progs;path7;1;
@progs;path8;1;
user8;no;@progs;path5;1;
user8;no;@progs;path6;1;
user8;no;@progs;path7;1;
user8;no;@progs;path8;1;
user9;no;@progs;path5;1;
user9;no;@progs;path6;1;
user9;no;@progs;path7;1;
user9;no;@progs;path8;1;
user9;no;@progs;path10;1;
user10;no;@progs;path5;1;
user10;no;@progs;path6;1;
user10;no;@progs;path7;1;
user10;no;@progs;path8;1;
user10;no;@progs;path9;1;
...

Z uzyciem bash (awk,sed,itp...)
Dzieki